Three-team tie for two wild-card spots? The chaos would be great
Two games separate the three teams at the top of the American League wild-card race, leaving open the possibility of a three-way tie. Here's what would happen.
Monday in Cleveland.
Tuesday in Texas.
Wednesday either back in Cleveland, or at Tampa Bay.
I like it. You root for your team in the American League wild-card race. I'm rooting for chaos.
We need the Rays to finish 3-2 on the road against the Yankees (two games) and Blue Jays (three games). We need the Indians to finish 4-1 at home against the White Sox (one game) and on the road against the Twins (four games).
And we need the Rangers to go 5-0 at home against the Astros (one game) and Angels (four games).
The Rays finish 91-71. The Indians finish 91-71. The Rangers finish 91-71.
There are other combinations, but you get the idea. It's not impossible.
Here's what would happen:
The Rays and Indians would play Monday in Cleveland, because in the head-to-head games between the three teams, the Indians had the best record (7-5) and the Rays had the second-best record (7-6). The winner of that game would be in the playoffs as the first wild-card team, and would host Wednesday's play-in game.
The loser of Monday's Rays-Indians game would fly to Texas to play the Rangers on Tuesday (the Rangers were a combined 5-8 head-to-head against Cleveland and Tampa Bay). The winner of Tuesday's game would be the second wild-card team, and would be the road team Wednesday.
Cleveland to Texas to Cleveland, or Cleveland to Texas to Tampa.
Our travel budget would hate it. Baseball fans without a rooting interest would love it.
So would I.
A three-team tie for two spots. Let's do it.