Cubs-Indians World Series Game 7 lineups: Schwarber stays second in batting order
This is it, the lineup entry for the last game of the year
By
Matt Snyder
•
1 min read
CLEVELAND -- Well, gang, we're here. This is the final MLB game of the year and it's for the top prize in the industry. A new World Series champion will be crowned based upon the result of Game 7 of the World Series, which takes place Wednesday night in Progressive Field.
Here are the lineups
Visiting Cubs (3-3)
1. Dexter Fowler, CF
2. Kyle Schwarber, DH
3. Kris Bryant, 3B
4. Anthony Rizzo, 1B
5. Ben Zobrist, LF
6. Addison Russell, SS
7. Willson Contreras, C
8. Jason Heyward, RF
9. Javier Baez, 2B
RHP Kyle Hendricks
No surprises there. That's the same batting order that produced nine runs in Game 6.
Home Indians (3-3)
1. Carlos Santana, DH
2. Jason Kipnis, 2B
3. Francisco Lindor, SS
4. Mike Napoli, 1B
5. Jose Ramirez, 3B
6. Lonnie Chisenhall, RF
7. Rajai Davis, CF
8. Coco Crisp, LF
9. Roberto Perez, C
RHP Corey Kluber
The notable change is Davis taking over center for Tyler Naquin, who had a rough go of it for the most part in Game 6.
